document.write( "Question 456799: find the x- and y-intercepts
\n" ); document.write( "f(x)=25x^2+10x+1
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Algebra.Com's Answer #313447 by lwsshak3(11628)\"\" \"About 
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find the x- and y-intercepts
\n" ); document.write( "f(x)=25x^2+10x+1
\n" ); document.write( "..
\n" ); document.write( "f(x)=25x^2+10x+1
\n" ); document.write( "find y-intercepts
\n" ); document.write( "set x=0, then solve for y
\n" ); document.write( "y=1
\n" ); document.write( "..
\n" ); document.write( "find x-intercepts
\n" ); document.write( "set y=0, then solve for x
\n" ); document.write( "25x^2+10x+1=0
\n" ); document.write( "solve by using quadratic formula as follows:
\n" ); document.write( "..
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "..
\n" ); document.write( "a=25, b=10, c=1
\n" ); document.write( "x=[-10ħsqrt(10^2-4*25*1)]/2*25
\n" ); document.write( "x=-10/50=1/5=0.2
\n" ); document.write( "ans:
\n" ); document.write( "y-intercept=1
\n" ); document.write( "x-intercepts=0.2 (multiplicity of 2, that is, both roots have the same value)
\n" ); document.write( "The graph below is a visual check on the answers: Note the y and x-intercepts.
\n" ); document.write( "Also, whenever you see on a graph the curve bounces off the x-axis, the root is a multiple root like this case.
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\n" ); document.write( "\n" ); document.write( "\"+graph%28+300%2C+300%2C+-2%2C+2%2C+-2%2C+2%2C+25x%5E2%2B10x%2B1%29+\"
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