document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=456779>Question 456779</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The common algorithm for calculating the roots of a quadratic equation by the quadratic formula requires considering several special cases in your code, including consideration of special cases when one or more coefficients vanish. Write appropriate comments for this algorithm so that the comments make it easy to see the different cases and how they are handled. Write accompanying documentation to explain the algorithm. Total target answer should be no more than 2 pages\r<BR>\n" );
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document.write( "I need help on this ASAP<BR>\n" );
document.write( "Tks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #313445 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=313445\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Times New Roman\" size=\"+2\">\r<BR>\n" );
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document.write( "Either share the particular \"common algorithm\" with which you are dealing, or go ask this question on a Computer Science website.\r<BR>\n" );
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document.write( "In general though, if your coefficients are a, b, and c, then the cases would be:\r<BR>\n" );
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document.write( "1.  a = 0; the code should return a message to the user that this is not a quadratic.\r<BR>\n" );
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document.write( "2.  b = 0, but a and c not equal to zero and the signs on a and c are opposite:  the code should return an answer <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large \pm\sqrt{-\frac{c}{a}}\">\r<BR>\n" );
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document.write( "3.  b = 0,  but a and c not equal to zero and the signs on a and c are the same:  the code should return either \"No solution over the reals\" or an answer of <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large \pm\,i\sqrt{\frac{c}{a}}\"> depending on whether the algorithm is designed to handle complex number roots or not.\r<BR>\n" );
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document.write( "4.  b = 0 and c = 0, then x = 0.\r<BR>\n" );
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document.write( "5.  a, b, and c non-zero, then:\r<BR>\n" );
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document.write( "5a.  if <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large b^2\ -\ 4ac\ =\ 0\">, then <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large x\ =\ -\frac{b}{2a}\"> and the single root has a multiplicity of 2.\r<BR>\n" );
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document.write( "5b.  if <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large b^2\ -\ 4ac\ >\ 0\">, then <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large x\ =\ \frac{-b\ \pm\ \sqrt{b^2\ -\ 4ac}}{2a}\">\r<BR>\n" );
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document.write( "5c.  if <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large b^2\ -\ 4ac\ <\ 0\">, then the algorithm should return either \"No solution over the reals\" or an answer of <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large x\ =\ \frac{-b\ \pm\ i\sqrt{-b^2\ +\ 4ac}}{2a}\"> depending on whether the algorithm is designed to handle complex number roots or not.\r<BR>\n" );
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document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi} + 1 = 0\"><BR>\n" );
document.write( "My calculator said it, I believe it, that settles it<BR>\n" );
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