document.write( "Question 456557: I am really struggling with this. Could you please show me step by step how to solve this?
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document.write( "The speed of train A is 20mph slower than the speed of train B. Train A travels 190 miles in the same time it takes train B to travel 290 miles. Find the speed of each train.\r
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document.write( "Thanks!! Was never good at word problems. \n" );
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Algebra.Com's Answer #313387 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Let a = speed of train A \n" ); document.write( "Let b = speed of train B \n" ); document.write( ": \n" ); document.write( "Write an equation for each statement: \n" ); document.write( ": \n" ); document.write( "\"the speed of train A is 20mph slower than the speed of train B.\" \n" ); document.write( "a = b - 20 \n" ); document.write( ": \n" ); document.write( "\" Train A travels 190 miles in the same time it takes train B to travel 290 miles. \n" ); document.write( "Write a time equation; time = dist/speed \n" ); document.write( "a's time = b's time \n" ); document.write( " \n" ); document.write( "From the 1st equation, replace a with (b-20), and you have: \n" ); document.write( " \n" ); document.write( "Cross multiply \n" ); document.write( "290(b-20) = 190b \n" ); document.write( "290b - 5800 = 190b \n" ); document.write( "290b - 190b = 5800 \n" ); document.write( "100b = 5800 \n" ); document.write( "b = \n" ); document.write( "b = 58 mph is train B \n" ); document.write( "then \n" ); document.write( "58 - 20 = 38 mph is Train A \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "We can confirm this solution by finding the time of each train (should be the same) \n" ); document.write( "190/38 = 5 hrs \n" ); document.write( "290/58 = 5 hrs \n" ); document.write( ": \n" ); document.write( "Did this make sense to you?\r \n" ); document.write( "\n" ); document.write( " Find the speed of each train. \n" ); document.write( " |