document.write( "Question 456650: At the begining of a walk, Roberto and Juaita are 6.6 miles apart. If they leave at the same time and wal in the same direction, Roberto overtakes Juanita in 11hours. If they wal towards each other, they meet in 1 hour. What are their speeds? \n" ); document.write( "
Algebra.Com's Answer #313367 by mananth(16946)\"\" \"About 
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Roberto speed = xmph
\n" ); document.write( "Juanita speed = y mph
\n" ); document.write( "same direction so subtract speed
\n" ); document.write( "effective speed = x-y
\n" ); document.write( "time = d/r\r
\n" ); document.write( "\n" ); document.write( "6.6/(x-y)=11\r
\n" ); document.write( "\n" ); document.write( "11x-11y=6.6.....1\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Opposite direction
\n" ); document.write( "add up speeds
\n" ); document.write( "effective speed = x+y
\n" ); document.write( "time = 6.6/(x+y)
\n" ); document.write( "6.6/(x+y)=1
\n" ); document.write( "x+y=6.6..........2\r
\n" ); document.write( "\n" ); document.write( "11x-11y =6.6 .............1
\n" ); document.write( "x+y=6.6 .............2
\n" ); document.write( "
\n" ); document.write( "multiply (1)by 1
\n" ); document.write( "Multiply (2) by 11
\n" ); document.write( "11x-11y=6.6
\n" ); document.write( "11x+11y =72.6
\n" ); document.write( "Add the two equations
\n" ); document.write( "22x=79.2
\n" ); document.write( "/22
\n" ); document.write( "x=3.60 mph
\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "11x-11y=6.6
\n" ); document.write( "39.6-11y=6.6
\n" ); document.write( "-11y=6.6-39.6
\n" ); document.write( "-11y=-33
\n" ); document.write( "y=3.00 mph
\n" ); document.write( "
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