document.write( "Question 47446: Help\r
\n" ); document.write( "\n" ); document.write( "log5 x = 3 \n" ); document.write( "
Algebra.Com's Answer #31329 by longjonsilver(2297)\"\" \"About 
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this is asking: what number (here x) is equal to 5^3. Answer is 5*5*5 --> 125\r
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\n" ); document.write( "\n" ); document.write( "so in base 5 logs, log125 is equal to 3.\r
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\n" ); document.write( "\n" ); document.write( "In terms of manipulating the equation, we have
\n" ); document.write( "log5 x = 3\r
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\n" ); document.write( "\n" ); document.write( "we do not want the log bit, so we need to remove it. We remove anything in maths by doing the opposite. The opposite of log5 is to raise to base 5:\r
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\n" ); document.write( "\n" ); document.write( "log5 x = 3 becomes
\n" ); document.write( "5^log5 x = 5^3\r
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\n" ); document.write( "\n" ); document.write( "and the \"5^log5\" cancels each other out. That is the point of doing it. This leaves:\r
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\n" ); document.write( "\n" ); document.write( "x = 5^3
\n" ); document.write( "x = 125\r
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