document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=47445>Question 47445</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have problems with logs please help\r<BR>\n" );
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document.write( "log4 (x - 2) + log4 (x - 2) = 1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #31327 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=31327\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log4 (x - 2) + log4 (x - 2) = 1\r<BR>\n" );
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document.write( "two logs added is really just one log with multiplied terms:<BR>\n" );
document.write( "log4 ((x - 2)(x - 2)) = 1\r<BR>\n" );
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document.write( "Now we raise both side to base 4 to remove the log term:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+x%5E2+-+4x+%2B+4+=+4+ ALIGN=MIDDLE  ALT=\"+x%5E2+-+4x+%2B+4+=+4+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+x%5E2+-+4x+=+0+ ALIGN=MIDDLE  ALT=\"+x%5E2+-+4x+=+0+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x(x-4) = 0\r<BR>\n" );
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document.write( "so either x=0 or x-4=0<BR>\n" );
document.write( "so we have x=0 or x=4\r<BR>\n" );
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document.write( "Logs are fairly straight forward.... just learn the 3 basic laws and apply them properly, as i have done above.\r<BR>\n" );
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document.write( "jon<BR>\n" );
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