document.write( "Question 47449: Solve by completing the square. Other methods will receive no credit.
\n" ); document.write( "x2 + 6x + 2 = 0
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #31326 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Solve by completing the square.
\n" ); document.write( "\"x%5E2%2B6x%2B2+=0\" First, subtract 2 from both sides of the equation.
\n" ); document.write( "\"x%5E2%2B6x+=+-2\" Complete the square on the left side by adding the square of half the x-coefficient \"%286%2F2%29%5E2+=+9\" to both sides of the equation.
\n" ); document.write( "\"x%5E2%2B6x%2B9+=+7\" Now factor the left side.
\n" ); document.write( "\"%28x%2B3%29%28x%2B3%29+=+7\"
\n" ); document.write( "\"%28x%2B3%29%5E2+=+7\" Take the square root of both sides.
\n" ); document.write( "\"x%2B3+=+plus+or+-sqrt%287%29\" Subtract 3 from both sides.\r
\n" ); document.write( "\n" ); document.write( "\"x+=+-3%2B-sqrt%287%29\"
\n" ); document.write( "
\n" );