document.write( "Question 456455: If the perimeter of a certain rectangle is 78cm. and the width is 12cm., what is the length?\r
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document.write( "P=2w + 2l\r
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document.write( "So, my equation looks like this: 78 = 12w + 2l (I'm not even sure that's right)\r
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document.write( "This is what I came up with:\r
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document.write( "I am trying to isolate L.....
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document.write( "78 = 12w + 2l
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document.write( "2 2 \r
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document.write( "At this point I get confused as to what to do next.....please help? \r
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Algebra.Com's Answer #313259 by zeti68(10)![]() ![]() ![]() You can put this solution on YOUR website! Hi, \n" ); document.write( "P=2w + 2L \n" ); document.write( "78 = 2(12) + 2L \n" ); document.write( "78=24+2L \n" ); document.write( "78-24=2L \n" ); document.write( "54=2L \n" ); document.write( "54/2=L \n" ); document.write( "L=27\r \n" ); document.write( "\n" ); document.write( "Answer \n" ); document.write( "length=27cm \n" ); document.write( " \n" ); document.write( " |