document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=456455>Question 456455</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the perimeter of a certain rectangle is 78cm. and the width is 12cm., what is the length?\r<BR>\n" );
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document.write( "P=2w + 2l\r<BR>\n" );
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document.write( "So, my equation looks like this: 78 = 12w + 2l (I'm not even sure that's right)\r<BR>\n" );
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document.write( "This is what I came up with:\r<BR>\n" );
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document.write( "I am trying to isolate L.....<BR>\n" );
document.write( "78 = 12w + 2l<BR>\n" );
document.write( "---------------<BR>\n" );
document.write( "2        2        \r<BR>\n" );
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document.write( "At this point I get confused as to what to do next.....please help? \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #313257 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=313257\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 78=2*12+2l<BR>\n" );
document.write( "78=24+2l<BR>\n" );
document.write( "54=2l<BR>\n" );
document.write( "l=27<BR>\n" );
document.write( "check<BR>\n" );
document.write( "2*12+2*27=78<BR>\n" );
document.write( "24+54=78<BR>\n" );
document.write( "ok<BR>\n" );
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