document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=456441>Question 456441</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 34ft, the length is 3ft longer than the width. Find the dimension<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #313246 by </B><A HREF=/tutors/aboutme.mpl?userid=zeti68><B>zeti68(10)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=zeti68><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=313246\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi,\r<BR>\n" );
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document.write( "length=L<BR>\n" );
document.write( "width=W\r<BR>\n" );
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document.write( "34= 2(L+W)<BR>\n" );
document.write( "L= W+3\r<BR>\n" );
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document.write( "34= 2(W+3+W)= 2(2W+3)= 4W+6<BR>\n" );
document.write( "34-6=4W<BR>\n" );
document.write( "28= 4W<BR>\n" );
document.write( "28/4=W<BR>\n" );
document.write( "W= 7\r<BR>\n" );
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document.write( "L= 7+3<BR>\n" );
document.write( "L=10\r<BR>\n" );
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document.write( "Answer: length=7 ft<BR>\n" );
document.write( "         width=10 ft </SPAN>\n" );
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