document.write( "Question 47444: Please help\r
\n" ); document.write( "\n" ); document.write( "In a chemistry class, 6 liters of a 4% silver iodide solution must be mixed with a 10% solution to get a 6%
\n" ); document.write( "solution. How many liters of the 10% solution are needed?
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Algebra.Com's Answer #31324 by longjonsilver(2297)\"\" \"About 
You can put this solution on YOUR website!
Mixture questions are all about BEFORE = AFTER since the \"BEFORE's\" mix to become the \"AFTER\", so they have to be \"equal\".\r
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\n" ); document.write( "\n" ); document.write( "Right, a definition so we know what x is: Let x be the amount of the 10% solution.
\n" ); document.write( "Once mixed, how much will we have? we will have (x+6) litres, surely? :-)\r
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\n" ); document.write( "\n" ); document.write( "BEFORE:
\n" ); document.write( "0.04*6 and 0.10x\r
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\n" ); document.write( "\n" ); document.write( "AFTER:
\n" ); document.write( "0.06*(x+6)\r
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\n" ); document.write( "\n" ); document.write( "So, 0.04*6 + 0.10x = 0.06*(x+6)
\n" ); document.write( "0.24 + 0.10x = 0.06x + 0.36
\n" ); document.write( "0.24 + 0.04x = 0.36
\n" ); document.write( "0.04x = 0.12
\n" ); document.write( "x = 0.12/0.04
\n" ); document.write( "x = 3litres\r
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\n" ); document.write( "\n" ); document.write( "jon
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