document.write( "Question 456387: Find three consecutive integers such that the sum of twice the first and 4 times the second is equal to 20 more than twice the third. \n" ); document.write( "
Algebra.Com's Answer #313222 by checkley79(3341)\"\" \"About 
You can put this solution on YOUR website!
Let x, x+1 & x+2 be the three integers.
\n" ); document.write( "2x+4(x+1)=2(x+2)+20
\n" ); document.write( "2x+4x+4=2x+4+20
\n" ); document.write( "6x+4=2x+24
\n" ); document.write( "6x-2x=24-4
\n" ); document.write( "4x=20
\n" ); document.write( "x=20/4
\n" ); document.write( "x=5 ans.
\n" ); document.write( "Proof:
\n" ); document.write( "2*5+4(5+1)=2(5+2)+20
\n" ); document.write( "10+4*6=2*7+20
\n" ); document.write( "10+24=14+20
\n" ); document.write( "34=34\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );