document.write( "Question 456387: Find three consecutive integers such that the sum of twice the first and 4 times the second is equal to 20 more than twice the third. \n" ); document.write( "
Algebra.Com's Answer #313222 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! Let x, x+1 & x+2 be the three integers. \n" ); document.write( "2x+4(x+1)=2(x+2)+20 \n" ); document.write( "2x+4x+4=2x+4+20 \n" ); document.write( "6x+4=2x+24 \n" ); document.write( "6x-2x=24-4 \n" ); document.write( "4x=20 \n" ); document.write( "x=20/4 \n" ); document.write( "x=5 ans. \n" ); document.write( "Proof: \n" ); document.write( "2*5+4(5+1)=2(5+2)+20 \n" ); document.write( "10+4*6=2*7+20 \n" ); document.write( "10+24=14+20 \n" ); document.write( "34=34\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |