document.write( "Question 456296: I am TOTALLY lost on this one :( PLEASE HELP!! All of the fractions really confuse me. I'm supposed to solve for x...\r
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\n" ); document.write( "\n" ); document.write( "2/3 + 1/(2 2/5) - 1/x = 1/3 - 1/(2 2/3)\r
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Algebra.Com's Answer #313169 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
OK
\n" ); document.write( "I'm assuming that 2 2/5=2 and 2/5ths and that 2 2/3=2 and 2/3rds\r
\n" ); document.write( "\n" ); document.write( "First 2 2/5=12/5
\n" ); document.write( "and
\n" ); document.write( "2 2/3=8/3
\n" ); document.write( "Now lets rewrite the equation:
\n" ); document.write( "2/3 + 1/(12/5)-1/x=1/(8/3)
\n" ); document.write( "Next, 1/(12/5)=5/12 (multiply numerator and denominator by 5/12)
\n" ); document.write( "and
\n" ); document.write( "1/(8/3)=3/8
\n" ); document.write( "Lets now rewrite the equation again:
\n" ); document.write( "2/3 + 5/12 - 1/x=3/8 subtract 2/3 and also 5/12 from each side of the equation:
\n" ); document.write( "-1/x=3/8-2/3-5/12 or
\n" ); document.write( "-1/x=9/24-16/24-10/24 combine like terms
\n" ); document.write( "-1/x=-2/24 cross multiply
\n" ); document.write( "-2x=-24
\n" ); document.write( "x=12--------------ans\r
\n" ); document.write( "\n" ); document.write( "Hope this helps--ptaylor
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