document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=456288>Question 456288</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have attempted this problem about 6 times now, and I always get stuck :( I'm supposed to solve for a but I cant figure it out! Can someone help me? Also, if you could include steps that would be wonderful :)\r<BR>\n" );
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document.write( "solve for a <BR>\n" );
document.write( "a - (3a-6)/6 = (3a+2)/3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #313154 by </B><A HREF=/tutors/aboutme.mpl?userid=rfer><B>rfer(16322)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=313154\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3(a-(3a-6)/6)=3a+2<BR>\n" );
document.write( "3(a-(3a-1)=3a+2<BR>\n" );
document.write( "3(a-3a+1)=3a+2<BR>\n" );
document.write( "3a-9a+3=3a+2<BR>\n" );
document.write( "-9a=-1<BR>\n" );
document.write( "a=1/9 </SPAN>\n" );
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