document.write( "Question 456209: 2x^3+4x^2-18x-36=0 \n" ); document.write( "

Algebra.Com's Answer #313124 by nerdybill(7384) $\"\"$ $\"About$

You can put this solution on YOUR website!
2x^3+4x^2-18x-36=0
\n" ); document.write( "rearrange terms:
\n" ); document.write( "2x^3-18x+4x^2-36=0
\n" ); document.write( "group:
\n" ); document.write( "(2x^3-18x)+(4x^2-36)=0
\n" ); document.write( "factor each group:
\n" ); document.write( "2x(x^2-9)+4(x^2-9)=0
\n" ); document.write( "(x^2-9)(2x+4)=0
\n" ); document.write( "the term on left is a \"difference of squares\":
\n" ); document.write( "(x-3)(x+3)(2x+4)=0
\n" ); document.write( "x = {-3, 3, -2} \n" ); document.write( "

\n" );