document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=456045>Question 456045</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Trying to help my son but it's been waaaay too long ago:\r<BR>\n" );
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document.write( "x^2 + y^2 +4x - 6y -3 = 0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #313059 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=313059\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x^2 + y^2 +4x - 6y -3 = 0<BR>\n" );
document.write( "..<BR>\n" );
document.write( "To find out what kind of conic this equation is, we must put it in standard form by completing the square. This is how you do it:<BR>\n" );
document.write( "completing the square<BR>\n" );
document.write( "(x^2+4x+4)+(y^2-6y+9)=3+4+9=16<BR>\n" );
document.write( "(x+2)^2+(y-3)^2=16<BR>\n" );
document.write( "This equation is a circle with center at (-2,3) and radius=&#8730;16=4<BR>\n" );
document.write( "see the graph below as a visual check on the answer<BR>\n" );
document.write( "..<BR>\n" );
document.write( "y=(16-(x+2)^2)^.5+3<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+%2816-%28x%2B2%29%5E2%29%5E.5%2B3%2C-%2816-%28x%2B2%29%5E2%29%5E.5%2B3%29+ ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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