document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=456035>Question 456035</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Finf the rational roots of (4x to the thrid power -3x-1=0). Explain the process you use and show work </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #313044 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=313044\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the rational roots of (4x to the third power -3x-1=0).<BR>\n" );
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document.write( "4x^3-3x-1 = 0<BR>\n" );
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document.write( "The sum of the coefficients is zero so x=1 is a root<BR>\n" );
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document.write( "Use synthetic division:<BR>\n" );
document.write( "1).....4....0....-3....-1<BR>\n" );
document.write( "........4....4.....1...|..0\r<BR>\n" );
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document.write( "Quotient: 4x^2+4x+1<BR>\n" );
document.write( "Solve 4x^2+4x+1 = 0 <BR>\n" );
document.write( "Factor:<BR>\n" );
document.write( "(2x+1)(2x+1) = 0<BR>\n" );
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document.write( "x = -1/2 with multiplicity 2<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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