document.write( "Question 455925: I can't graph this equation.
\n" ); document.write( "x + 3y= 6
\n" ); document.write( "How do I use the intercepts? \n" ); document.write( "

Algebra.Com's Answer #312992 by lwsshak3(11628) $\"\"$ $\"About$

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I can't graph this equation.
\n" ); document.write( "x + 3y= 6
\n" ); document.write( "How do I use the intercepts
\n" ); document.write( "..
\n" ); document.write( "This is an equation of a straight line so write it into its standard slope-intercept form to get some idea of what it looks like graphically:\r
\n" ); document.write( "\n" ); document.write( "y=mx+b, with m=slope, and b=y-intercept\r
\n" ); document.write( "\n" ); document.write( "for given equation:
\n" ); document.write( "3y=-x+6
\n" ); document.write( "y=-x/3+2
\n" ); document.write( "so the slope is -1/3 and y-intercept=2
\n" ); document.write( "To graph this equation all you need are two points.
\n" ); document.write( "Start at the y-intercept 2 then find the second point using the slope(rise=-1, run=3)=∆y/∆x
\n" ); document.write( "As a check, you can find a third point by setting y=0 to find the x-intercept=6
\n" ); document.write( "See the following graph.
\n" ); document.write( " $\"+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+-x%2F3%2B2%29+\"$ \n" ); document.write( "

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