document.write( "Question 455916: You know that Bob, Sue, Joanne and Jasper all have birthdays in June. If we list how many ways these four people all have birthdays on different days in June, how many arrangements of 4 days would there be in the list? \n" ); document.write( "

Algebra.Com's Answer #312971 by solver91311(24713) $\"\"$ $\"About$

You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "In this problem, order matters. That is to say that Bob on June 1, Sue on June 2, Joanne on June 3, and Jasper on June 4 is a different outcome than, say, Bob on June 4, Sue on June 3, Joanne on June 2, and Jasper on June 1. Since order matters, you need the number of permutations of 30 things taken 4 at a time. How do we know it is 30? Because June has 30 days.\r
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\n" ); document.write( "\n" ); document.write( "The number of permutations of

things taken

at a time is given by:\r
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\n" ); document.write( "\n" ); document.write( "in your case:\r
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\n" ); document.write( "\n" ); document.write( "You can do your own arithmetic.\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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$\"The$

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