document.write( "Question 455868: How many quarts of a 20% alcohol solution and how many quarts of pure alcohol should be mixed together to obtain 100 quarts that contain 30% alcohol?\r
\n" ); document.write( "\n" ); document.write( "Can you please help me! I am completely lost. \n" ); document.write( "
Algebra.Com's Answer #312952 by stanbon(75887)\"\" \"About 
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How many quarts of a 20% alcohol solution and how many quarts of pure alcohol should be mixed together to obtain 100 quarts that contain 30% alcohol?\r
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\n" ); document.write( "Equation:
\n" ); document.write( "Quantity Equation:: x + y = 100 quarts
\n" ); document.write( "Alcohol Equation:: 0.20x+y = 0.30*100
\n" ); document.write( "---
\n" ); document.write( "Multiply thru 1st by 20
\n" ); document.write( "Multiply thru 2nd by 100
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\n" ); document.write( "20x + 20y = 20*100
\n" ); document.write( "20x +100y = 30*100
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\n" ); document.write( "Subtract and solve for \"y\":
\n" ); document.write( "80y = 10*100
\n" ); document.write( "y = 100/8 = 12.5 quarts (amt of pure alcohol needed)
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\n" ); document.write( "Solve for \"x\":
\n" ); document.write( "x + 12.5 = 100
\n" ); document.write( "x = 87.5 quarts (amt of 20% alcohol needed)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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