document.write( "Question 455868: How many quarts of a 20% alcohol solution and how many quarts of pure alcohol should be mixed together to obtain 100 quarts that contain 30% alcohol?\r
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document.write( "Can you please help me! I am completely lost. \n" );
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Algebra.Com's Answer #312951 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! t = quarts of 20% \n" ); document.write( "p = quarts of pure \n" ); document.write( "----------- \n" ); document.write( "t + p = 100 (total liquid) \n" ); document.write( "0.20t + 1.00p = 0.30*100 (total alcohol) \n" ); document.write( "2t + 10p = 300 \n" ); document.write( "t = 100 - p (from 1st eqn) \n" ); document.write( "2(100-p) + 10p = 300 \n" ); document.write( "200 - 2p + 10p = 300 \n" ); document.write( "8p = 100 \n" ); document.write( "p = 12.5 quarts of pure \n" ); document.write( "t = 87.5 quarts of 20% \n" ); document.write( " \n" ); document.write( " |