document.write( "Question 455873: How would I solve this equation? I have to solve for y:\r
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document.write( "20 + 3/4(12+y) = 3/2y - 10\r
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document.write( "Please help me out! :) Also, if you can show the steps? Thanks a bunch!! \n" );
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Algebra.Com's Answer #312950 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 20 + 3/4(12+y) = 3/2y - 10 \n" ); document.write( "--- \n" ); document.write( "Add 10 to both sides: \n" ); document.write( "---- \n" ); document.write( "30 + (3/4)(12+y) = (3/2)y \n" ); document.write( "---- \n" ); document.write( "30 + 9 + (3/4) = (6/4)y \n" ); document.write( "==== \n" ); document.write( "39 = (3/4)y \n" ); document.write( "--- \n" ); document.write( "13 = (1/4)y \n" ); document.write( "y = 52 \n" ); document.write( "================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============ \n" ); document.write( " |