document.write( "Question 455819: Jerry is experimenting with chemicals in the laboratory. He mixes a solution that is 10% acid with a solution that is 30% acid. How much of the 30% acid solution will be needed to make 40 liters of solution that is 25% acid? \n" ); document.write( "
Algebra.Com's Answer #312915 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! He mixes a solution that is 10% acid with a solution that is 30% acid. How much of the 30% acid solution will be needed to make 40 liters of solution that is 25% acid? \n" ); document.write( "----- \n" ); document.write( "Equation: \n" ); document.write( "acid + acid = acid \n" ); document.write( "----- \n" ); document.write( "0.10x + 0.30(40-x) = 0.25*40 \n" ); document.write( "--- \n" ); document.write( "Multiply thru by 100 to get: \n" ); document.write( "10x + 30*40 - 30x = 25*40 \n" ); document.write( "----- \n" ); document.write( "-20x = -5*40 \n" ); document.write( "x = 10 liters (amt. of 10% solution needed) \n" ); document.write( "--- \n" ); document.write( "40-x = 30 liters (amt. of 30^ acid needed) \n" ); document.write( "============================================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============ \n" ); document.write( " |