document.write( "Question 455706: how do you graph y= -2x^2+8 and how do you find the vertex and the roots
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Algebra.Com's Answer #312860 by stanbon(75887)\"\" \"About 
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how do you graph y= -2x^2+8 and how do you find the vertex and the roots\r
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\n" ); document.write( "Vertex occurs at x = -b/(2a) = -0/(-4) = 0
\n" ); document.write( "f(0) = -2*0^2+8 = 8
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\n" ); document.write( "Vertex: (0,8)
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\n" ); document.write( "Roots = ?
\n" ); document.write( "Solve -2x^2+8 = 0
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\n" ); document.write( "-2(x^2-4) = 0
\n" ); document.write( "x^2 - 4 = 0
\n" ); document.write( "(x-2)(x+2) = 0
\n" ); document.write( "x = 2 or x = -2
\n" ); document.write( "Those are the roots.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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