document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=455264>Question 455264</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the equation for x: 2log base 5 of x + log base 5 of 3 = log base 5(1/125)  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #312786 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=312786\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve the equation for x: 2log base 5 of x + log base 5 of 3 = log base 5(1/125)<BR>\n" );
document.write( "..<BR>\n" );
document.write( "2log5(x)+log5(3)=log5(1/125)=log5(5^-3)=-3   (log of the base^x = x)<BR>\n" );
document.write( "log5(3x^2) (exponent and multiplication rules)<BR>\n" );
document.write( "Convert to exponential form: (base(5) raised to log of number(-3)=number(3x^2)<BR>\n" );
document.write( "5^-3=3x^2<BR>\n" );
document.write( "x^2=1/125*3<BR>\n" );
document.write( "x=1/(5&#8730;5*&#8730;3)=1/(5&#8730;15)<BR>\n" );
document.write( "x=&#8730;15/75  </SPAN>\n" );
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