document.write( "Question 455587: sin(π/2-x)cot(π/2+x)=-sinx
\n" ); document.write( "solve the left side to make it right. \n" ); document.write( "

Algebra.Com's Answer #312771 by lwsshak3(11628) $\"\"$ $\"About$

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sin(π/2-x)cot(π/2+x)=-sinx
\n" ); document.write( "solve the left side to make it right.
\n" ); document.write( "..
\n" ); document.write( "sin(π/2-x)cot(π/2+x)
\n" ); document.write( "sin(π/2-x)=įos x
\n" ); document.write( "cot(π/2+x)=cos(π/2+x)/sin(π/2+x)
\n" ); document.write( "cos(π/2+x)=(cos(π/2)cosx)-(sin(π/2)sinx)=-sin x
\n" ); document.write( "sin(π/2+x)=(sin(π/2)cosx)-(cos(π/2)sinx)]=cos x
\n" ); document.write( "(cos x)(-sin x/cos x)
\n" ); document.write( "=-sinx
\n" ); document.write( "left side = right side \n" ); document.write( "

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