document.write( "Question 455472: Find, to the nearest degree all of the values of x.. 2 cos^2 x + 2 sin x - 1 = 0 \n" ); document.write( "
Algebra.Com's Answer #312758 by lwsshak3(11628)\"\" \"About 
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Find, to the nearest degree all of the values of x.. 2 cos^2 x + 2 sin x - 1 = 0
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\n" ); document.write( "2 cos^2 x + 2 sin x - 1 = 0
\n" ); document.write( "use following quadratic formula to solve for cos x:
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\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "..
\n" ); document.write( "a=2, b=2, c=-1
\n" ); document.write( "cos x=[-2±sqrt(2^2-4*2*-1)]2*2
\n" ); document.write( "cos x=(-2±√12)/4)
\n" ); document.write( "cos x=(-2±2√3)/4
\n" ); document.write( "cos x=-1/2±√3/2
\n" ); document.write( "cos x=-1/2-√3)/2=-1.366 (reject,(-1 < cos x < 1))
\n" ); document.write( "or
\n" ); document.write( "cos x=-1/2+√3)/2=.366
\n" ); document.write( "x=69º+2πn, 291º+2πn (n= any integer)
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