document.write( "Question 455472: Find, to the nearest degree all of the values of x.. 2 cos^2 x + 2 sin x - 1 = 0 \n" ); document.write( "
Algebra.Com's Answer #312758 by lwsshak3(11628) ![]() You can put this solution on YOUR website! Find, to the nearest degree all of the values of x.. 2 cos^2 x + 2 sin x - 1 = 0 \n" ); document.write( ".. \n" ); document.write( "2 cos^2 x + 2 sin x - 1 = 0 \n" ); document.write( "use following quadratic formula to solve for cos x: \n" ); document.write( ".. \n" ); document.write( " \n" ); document.write( ".. \n" ); document.write( "a=2, b=2, c=-1 \n" ); document.write( "cos x=[-2±sqrt(2^2-4*2*-1)]2*2 \n" ); document.write( "cos x=(-2±√12)/4) \n" ); document.write( "cos x=(-2±2√3)/4 \n" ); document.write( "cos x=-1/2±√3/2 \n" ); document.write( "cos x=-1/2-√3)/2=-1.366 (reject,(-1 < cos x < 1)) \n" ); document.write( "or \n" ); document.write( "cos x=-1/2+√3)/2=.366 \n" ); document.write( "x=69º+2πn, 291º+2πn (n= any integer) \n" ); document.write( " |