document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=455508>Question 455508</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The number of hours h that it takes m men to assemble x machines varies directly as the number of machines and inversely as the number of men. If four men can assemble 12 machines in four hours, how many men are needed to assemble 36 machines in eight hours? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #312734 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=312734\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4 men x 4 hours=16 man/hours<BR>\n" );
document.write( "12 machines/16 man hours=3/4 machine per man-hour<BR>\n" );
document.write( "36 machines/8 hours=9/2 machine/hour<BR>\n" );
document.write( "(9/2 machine/hour)/(3/4 machine/man)=6 men<BR>\n" );
document.write( "6 men x 8 hours x 3/4 machine=36 total machines.. </SPAN>\n" );
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