document.write( "Question 455403: 2.) In 1992, the FAA conducted 86,991 pre-employment drug tests on job applicants who were to be engaged in safety and security-related jobs, and found that 1,143 were positive.
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document.write( "(a) Construct a 95 percent confidence interval for the population proportion of positive drug tests.
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document.write( "(b) Why is the normality assumption not a problem, despite the very small value of p? (Data are from Flying 120, no.11[November 1993]. P 31.)\r
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Algebra.Com's Answer #312682 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 2.) In 1992, the FAA conducted 86,991 pre-employment drug tests on job applicants who were to be engaged in safety and security-related jobs, and found that 1,143 were positive. \n" ); document.write( "--- \n" ); document.write( "phat = 1143/86991 = 0.01314\r \n" ); document.write( "\n" ); document.write( "(a) Construct a 95 percent confidence interval for the population proportion of positive drug tests. \n" ); document.write( "--- \n" ); document.write( "ME = 1.96*sqrt[0.01314*0.98696/86991] = 0.000757 \n" ); document.write( "----------------------- \n" ); document.write( "95% CI: 0.01314-0.000757 < p < 0.01314+0.000757 \n" ); document.write( "95% CI: 0.012383 < p < 0.013897 \n" ); document.write( "================== \n" ); document.write( "(b) Why is the normality assumption not a problem, despite the very small value of p? \n" ); document.write( "Ample sample size. \n" ); document.write( "===================== \n" ); document.write( "cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |