document.write( "Question 455421: A list of numbers have mean 7 and standard deviation 2.5. If x is a number in the list that is 2 standard deviation above mean then what is the value of x ?
\n" ); document.write( "please explain the procedure
\n" ); document.write( "thank you
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Algebra.Com's Answer #312672 by stanbon(75887)\"\" \"About 
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A list of numbers have mean 7 and standard deviation 2.5. If x is a number in the list that is 2 standard deviation above mean then what is the value of x ?
\n" ); document.write( "please explain the procedure
\n" ); document.write( "---------------
\n" ); document.write( "Since z = (x-u)/s, x = zs+u
\n" ); document.write( "---
\n" ); document.write( "You have
\n" ); document.write( "u = 7
\n" ); document.write( "s = 2.5
\n" ); document.write( "z = 2
\n" ); document.write( "---
\n" ); document.write( "So, x = 2*2.5+7
\n" ); document.write( "x = 12
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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