document.write( "Question 455112: please i need help, to find the equation of the line that passing through (-2,4) and having the
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document.write( "(a) slope of 7/16.
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document.write( "(b) parallel to the 5x-3y=3
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document.write( "(c) passing through the orgin
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document.write( "(d) parallel to the y-axis. \n" );
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Algebra.Com's Answer #312642 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! find the equation of the line that passing through (-2,4) and having the \n" ); document.write( "(a) slope of 7/16. \n" ); document.write( "Use point/slope form: y - y1 = m(x - x1) \n" ); document.write( "y - 4 = \n" ); document.write( "y - 4 = \n" ); document.write( "y - 4 = \n" ); document.write( "y = \n" ); document.write( "y = \n" ); document.write( "y = \n" ); document.write( ": \n" ); document.write( "(b) parallel to the 5x - 3y = 3 \n" ); document.write( "Find the slope, put in the point/intercept form \n" ); document.write( "5x - 3y = 3 \n" ); document.write( "-3y = -5x + 3 \n" ); document.write( "y had to be positive, mult both sides by -1 \n" ); document.write( "3y = 5x - 3 \n" ); document.write( "Divide both sides by 3 \n" ); document.write( "y = \n" ); document.write( "y = \n" ); document.write( "slope = \n" ); document.write( "y - 4 = \n" ); document.write( "y - 4 = \n" ); document.write( "y - 4 = \n" ); document.write( "y = \n" ); document.write( "y = \n" ); document.write( "y = \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "(c) passing through the origin \n" ); document.write( "slope = \n" ); document.write( "y = -2x is the equation passes thru 0,0 and -2,4 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "(d) parallel to the y-axis. \n" ); document.write( "x = -2 \n" ); document.write( " |