document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=455348>Question 455348</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two angles are supplementary. One angle is 240 less than three times the other. Find the measures of each angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #312627 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=312627\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \"Two angles are supplementary. One angle is 240 less than three times the other. Find the measures of each angle.\"\r<BR>\n" );
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document.write( "x = one angle<BR>\n" );
document.write( "3x - 240 = other angle\r<BR>\n" );
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document.write( "x + 3x - 240 = 180<BR>\n" );
document.write( "4x - 240 = 180 {combined like terms}<BR>\n" );
document.write( "4x = 420 {added 240 to both sides}<BR>\n" );
document.write( "x = 105 {divided both sides by 4}<BR>\n" );
document.write( "3x - 240 = 75 {substituted 105, in for x, into 3x - 240}\r<BR>\n" );
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document.write( "105 and 75 are the two angles<BR>\n" );
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document.write( " </SPAN>\n" );
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