document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=455325>Question 455325</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the system using the substitution method. If the system has no solution or an infinite number of solutions, state this.\r<BR>\n" );
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document.write( "5x+y=13<BR>\n" );
document.write( "2x=-3y </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #312622 by </B><A HREF=/tutors/aboutme.mpl?userid=ilana><B>ilana(307)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ilana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=312622\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Substitution method means make one of the equations \"x=_\" or \"y=_\", and then substitute that into the other equation.<BR>\n" );
document.write( "Since the first equation has a y with no coefficient, solve for y in that equation.<BR>\n" );
document.write( "5x + y = 13 --> y = 13 - 5x<BR>\n" );
document.write( "Now substitute \"13 - 5x\" for y in the second equation.<BR>\n" );
document.write( "2x = -3y --> 2x = -3(13 - 5x)<BR>\n" );
document.write( "Solve for x.<BR>\n" );
document.write( "2x = -39 + 15x<BR>\n" );
document.write( "39 = 15x - 2x<BR>\n" );
document.write( "39 = 13x<BR>\n" );
document.write( "x = 3<BR>\n" );
document.write( "Now solve for y using the equation y = 13 - 5x<BR>\n" );
document.write( "y = 13 - 5x<BR>\n" );
document.write( "y = 13 - 5(3)<BR>\n" );
document.write( "y = 13 - 15<BR>\n" );
document.write( "y = -2<BR>\n" );
document.write( "The solution is x=3, y=-2. </SPAN>\n" );
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