document.write( "Question 455337: a merchant has coffe with $8 a pound that she wishes to mix with 5 pounds of coffee worth $9 a pound to get a mixture that can be sold for $6 a pound. How many pounds of the $8 coffee should be used? \n" ); document.write( "
Algebra.Com's Answer #312609 by stanbon(75887)\"\" \"About 
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A merchant has coffee with $8 a pound that she wishes to mix with 5 pounds of coffee worth $9 a pound to get a mixture that can be sold for $6 a pound. How many pounds of the $8 coffee should be used?
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\n" ); document.write( "Equation:
\n" ); document.write( "value + value = value
\n" ); document.write( "8x + 9*5 = 6(x+5)
\n" ); document.write( "8x + 45 = 6x+30
\n" ); document.write( "2x = -15
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\n" ); document.write( "Notice this gives you a negative answer.
\n" ); document.write( "That shows you cannot add $8 coffee with $9 coffee
\n" ); document.write( "and expect to get $6 coffee.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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