document.write( "Question 455272: how much pure acid should be mixed with 6 gallons of a 50% acid solution to get a 70% acid solution? \n" ); document.write( "
Algebra.Com's Answer #312571 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
how much pure acid should be mixed with 6 gallons of a 50% acid solution to get a 70% acid solution?
\n" ); document.write( "-------
\n" ); document.write( "Eqquation:
\n" ); document.write( "acid + acid = acid
\n" ); document.write( "x + 0.50(6) = 0.70(x+6)
\n" ); document.write( "---
\n" ); document.write( "Multiply thru by 100 to get:
\n" ); document.write( "100x + 50*6 = 70x + 70*6
\n" ); document.write( "30x = 20*6
\n" ); document.write( "x = 4 gallons (amt. of pure acid needed)
\n" ); document.write( "======================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "=============
\n" ); document.write( "
\n" );