document.write( "Question 455272: how much pure acid should be mixed with 6 gallons of a 50% acid solution to get a 70% acid solution? \n" ); document.write( "
Algebra.Com's Answer #312571 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! how much pure acid should be mixed with 6 gallons of a 50% acid solution to get a 70% acid solution? \n" ); document.write( "------- \n" ); document.write( "Eqquation: \n" ); document.write( "acid + acid = acid \n" ); document.write( "x + 0.50(6) = 0.70(x+6) \n" ); document.write( "--- \n" ); document.write( "Multiply thru by 100 to get: \n" ); document.write( "100x + 50*6 = 70x + 70*6 \n" ); document.write( "30x = 20*6 \n" ); document.write( "x = 4 gallons (amt. of pure acid needed) \n" ); document.write( "====================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============= \n" ); document.write( " |