document.write( "Question 455215: if the area of an isosceles right triangle is 36mm^2, what is the perimeter? \n" ); document.write( "
Algebra.Com's Answer #312543 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! the base and height are equal \n" ); document.write( "b=h \n" ); document.write( "area \n" ); document.write( "1/2*b*h=36 \n" ); document.write( "b*h=72 \n" ); document.write( "b*b=72 \n" ); document.write( "b^2=72 \n" ); document.write( "b=h=6sqrt(2) \n" ); document.write( "the third side (hypotenuse) is s \n" ); document.write( "b^2+b^2=s^2 \n" ); document.write( "2b^2=s^2 \n" ); document.write( "s^2=144 \n" ); document.write( "s=12\r \n" ); document.write( "\n" ); document.write( "b+s+h=p \n" ); document.write( "perimeter \n" ); document.write( "b = 6 Sqrt[2], h = 6 Sqrt[2], p = 12 (1 + Sqrt[2]), s = 12 \n" ); document.write( "b=8.48528, h=8.48528, s=12, p=28.9706 \n" ); document.write( "perimeter= 28.9706 \n" ); document.write( " |