document.write( "Question 455215: if the area of an isosceles right triangle is 36mm^2, what is the perimeter? \n" ); document.write( "
Algebra.Com's Answer #312543 by richwmiller(17219)\"\" \"About 
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the base and height are equal
\n" ); document.write( "b=h
\n" ); document.write( "area
\n" ); document.write( "1/2*b*h=36
\n" ); document.write( "b*h=72
\n" ); document.write( "b*b=72
\n" ); document.write( "b^2=72
\n" ); document.write( "b=h=6sqrt(2)
\n" ); document.write( "the third side (hypotenuse) is s
\n" ); document.write( "b^2+b^2=s^2
\n" ); document.write( "2b^2=s^2
\n" ); document.write( "s^2=144
\n" ); document.write( "s=12\r
\n" ); document.write( "\n" ); document.write( "b+s+h=p
\n" ); document.write( "perimeter
\n" ); document.write( "b = 6 Sqrt[2], h = 6 Sqrt[2], p = 12 (1 + Sqrt[2]), s = 12
\n" ); document.write( "b=8.48528, h=8.48528, s=12, p=28.9706
\n" ); document.write( "perimeter= 28.9706
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