document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=455176>Question 455176</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the area of the sector given that the radius is 4.6 cm and the central angle (Theta) is 2.9 radians. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #312507 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=312507\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the area of the sector given that the radius <BR>\n" );
document.write( "is 4.6 cm and the central angle (Theta) is 2.9 radians.<BR>\n" );
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document.write( "Total Area of the circle = (pi)4.6^2<BR>\n" );
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document.write( "Fraction of the total area that is in that sector = 2.9/(6(pi))<BR>\n" );
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document.write( "Area in the sector = [2.9/(6(pi))] * [(pi)4.6^2] <BR>\n" );
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document.write( "= [2.9*4.6*2/6] <BR>\n" );
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document.write( "= 10.227.. sq. cm.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );