document.write( "Question 455036: This needs to be solved by the substitution method.
\n" ); document.write( "4x + 4y = 0
\n" ); document.write( "-8x + y = 72
\n" ); document.write( "

Algebra.Com's Answer #312503 by mananth(16946)\"\" \"About 
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4x+4y=0 .............1
\n" ); document.write( "y=72+8x ---------2
\n" ); document.write( "substitute y in (1)
\n" ); document.write( "4x+4(72+8x)=0
\n" ); document.write( "4x+288+32x=0
\n" ); document.write( "4x+32x=0-288
\n" ); document.write( "36x=-288
\n" ); document.write( "/36
\n" ); document.write( "x=-8
\n" ); document.write( "Plug the value of x in (1)
\n" ); document.write( "4x+4y=0
\n" ); document.write( "4*-8+4y=0
\n" ); document.write( "-32+4y=0
\n" ); document.write( "4y=32
\n" ); document.write( "/4
\n" ); document.write( "y=8
\n" ); document.write( "
\n" ); document.write( "
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