document.write( "Question 455094: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function and graph the function.\r
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document.write( "f(x)=12x^2-12x+4 \n" );
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Algebra.Com's Answer #312499 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function and graph the function. \n" ); document.write( "f(x)=12x^2-12x+4 \n" ); document.write( ". \n" ); document.write( "Line of symmetry: \n" ); document.write( "x = -b/(2a) \n" ); document.write( "x = -(-12)/(2*12) \n" ); document.write( "x = 12/24 \n" ); document.write( "x = 1/2 (line of symmetry) \n" ); document.write( ". \n" ); document.write( "Vertex: \n" ); document.write( "f(1/2) = 12(1/2)^2 - 12(1/2) + 4 \n" ); document.write( "f(1/2) = 12(1/4) - 6 + 4 \n" ); document.write( "f(1/2) = 3 - 6 + 4 \n" ); document.write( "f(1/2) = 1 \n" ); document.write( "vertex is at (1/2, 1) \n" ); document.write( ". \n" ); document.write( "Since the coefficient associated with the x^2 term is positive (think happy face) the vertex is a MINIMUM\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |