document.write( "Question 455094: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function and graph the function.\r
\n" ); document.write( "\n" ); document.write( "f(x)=12x^2-12x+4
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Algebra.Com's Answer #312499 by nerdybill(7384)\"\" \"About 
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Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function and graph the function.
\n" ); document.write( "f(x)=12x^2-12x+4
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\n" ); document.write( "Line of symmetry:
\n" ); document.write( "x = -b/(2a)
\n" ); document.write( "x = -(-12)/(2*12)
\n" ); document.write( "x = 12/24
\n" ); document.write( "x = 1/2 (line of symmetry)
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\n" ); document.write( "Vertex:
\n" ); document.write( "f(1/2) = 12(1/2)^2 - 12(1/2) + 4
\n" ); document.write( "f(1/2) = 12(1/4) - 6 + 4
\n" ); document.write( "f(1/2) = 3 - 6 + 4
\n" ); document.write( "f(1/2) = 1
\n" ); document.write( "vertex is at (1/2, 1)
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\n" ); document.write( "Since the coefficient associated with the x^2 term is positive (think happy face) the vertex is a MINIMUM\r
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