document.write( "Question 455144: Here's my problem :
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document.write( "When Fritz drives to work his trip takes 35 minutes, but when he takes the train it takes 15 minutes. Find the distance Fritz travels to work if the train travels an average of 80 miles per hour faster than his driving.\r
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document.write( "using the equation r=d/t ( I think that's the right way)\r
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document.write( "r/35 - r/15 = 80\r
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document.write( "This throws out an incorrect answer. can anyone point out my error in setting up this equation? \n" );
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Algebra.Com's Answer #312495 by mananth(16946)![]() ![]() You can put this solution on YOUR website! the times are given in minutes \n" ); document.write( "the speed is mph \n" ); document.write( "so convert time to hours \n" ); document.write( "35 minutes = 7/12 hours \n" ); document.write( "15 minutes = 1/4 hour \n" ); document.write( "........\r \n" ); document.write( "\n" ); document.write( "rate of car = r mph \n" ); document.write( "rate of train = r+80 mph \n" ); document.write( "........ \n" ); document.write( "distance = same \n" ); document.write( "d=rt \n" ); document.write( "7/12 * r = 1/4(r+80) \n" ); document.write( "7r/12 = r/4 +20 \n" ); document.write( "7r/12-r/4 =20 \n" ); document.write( "LCD = 12 \n" ); document.write( "multiply by LCD \n" ); document.write( "7r-3r=12*20 \n" ); document.write( "4r=240 \n" ); document.write( "r=60 mph rate of car. \n" ); document.write( "time = 7/12 \n" ); document.write( "d= rt \n" ); document.write( "d= 7/12 * 60 = 35 miles. \n" ); document.write( "..... \n" ); document.write( "CHECK \n" ); document.write( "speed of train = 140 mph \n" ); document.write( "d= 1/4 *140=35 miles\r \n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |