document.write( "Question 455117: Two cyclists leave a city at the same time, one going east and the other going west. the west bound cyclist at 18mph faster than the east bound cyclist. after 3 hours they are 108 miles apart. how fast is each cyclist riding? \n" ); document.write( "
Algebra.Com's Answer #312463 by mananth(16946)![]() ![]() You can put this solution on YOUR website! East bound x mph \n" ); document.write( "west bound x+ 18 \n" ); document.write( ".. \n" ); document.write( "They are going away from each other. \n" ); document.write( " \n" ); document.write( "So add up their speed. \n" ); document.write( " \n" ); document.write( "combined speed = x+x + 18 \n" ); document.write( "(2x+18) \n" ); document.write( "Time = 3 hours \n" ); document.write( "Distance =108 miles \n" ); document.write( "Distance = speed * time \n" ); document.write( "(2x+18)*3=108 \n" ); document.write( "6x+54=108 \n" ); document.write( "6x=108-54 \n" ); document.write( "6x=54 \n" ); document.write( "/6 \n" ); document.write( "x=9 mph East bound \n" ); document.write( "west bound 9+18=27 mph \n" ); document.write( " |