document.write( "Question 455117: Two cyclists leave a city at the same time, one going east and the other going west. the west bound cyclist at 18mph faster than the east bound cyclist. after 3 hours they are 108 miles apart. how fast is each cyclist riding? \n" ); document.write( "
Algebra.Com's Answer #312463 by mananth(16946)\"\" \"About 
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East bound x mph
\n" ); document.write( "west bound x+ 18
\n" ); document.write( "..
\n" ); document.write( "They are going away from each other.
\n" ); document.write( "
\n" ); document.write( "So add up their speed.
\n" ); document.write( "
\n" ); document.write( "combined speed = x+x + 18
\n" ); document.write( "(2x+18)
\n" ); document.write( "Time = 3 hours
\n" ); document.write( "Distance =108 miles
\n" ); document.write( "Distance = speed * time
\n" ); document.write( "(2x+18)*3=108
\n" ); document.write( "6x+54=108
\n" ); document.write( "6x=108-54
\n" ); document.write( "6x=54
\n" ); document.write( "/6
\n" ); document.write( "x=9 mph East bound
\n" ); document.write( "west bound 9+18=27 mph
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