document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=451678>Question 451678</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If A baker is making fudge and his recipe calls for thirty 75% cocoa chocolate squares. He looks in the cupboard and discovers he only has 60% cocoa and 85% cocoa. How many of each should he use to make his fudge? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #312450 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=312450\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+y=1<BR>\n" );
document.write( ".60x+.85y=.75<BR>\n" );
document.write( "60x+85y=75<BR>\n" );
document.write( "60x+60y=60<BR>\n" );
document.write( "25y=15<BR>\n" );
document.write( "y=15/25=3/5<BR>\n" );
document.write( "--------------<BR>\n" );
document.write( "85x+85y=85<BR>\n" );
document.write( "60x+85y=75<BR>\n" );
document.write( "25x=10<BR>\n" );
document.write( "x=10/25=2/5<BR>\n" );
document.write( "The baker needs to use 2 parts of 60% cocoa for every 3 parts of 85% cocoa in his recipe.. </SPAN>\n" );
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