document.write( "Question 455082: How many gallons of a 60% salt solution must be mixed with 30 gallons of a 13% solution to obtain a solution that is 50% salt? \n" ); document.write( "
Algebra.Com's Answer #312434 by josmiceli(19441)\"\" \"About 
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Let \"a\" = gallons of 60% solution needed
\n" ); document.write( "given:
\n" ); document.write( "\"+.6a+\" = gallons of salt in 60% solution
\n" ); document.write( "\"+.13%2A30+=+3.9+\" = gallons of salt in 60% solution
\n" ); document.write( "\"+%28.6a+%2B+3.9%29+%2F+%28+a+%2B+30%29+=+.5+\"
\n" ); document.write( "\"+.6a+%2B+3.9+=+.5%2A%28+a+%2B+30+%29+\"
\n" ); document.write( "\"+.6a+%2B+3.9+=+.5a+%2B+15+\"
\n" ); document.write( "\"+.1a+=+11.1+\"
\n" ); document.write( "\"+a+=+111+\"
\n" ); document.write( "111 gallons of 60% solution are needed
\n" ); document.write( "check answer:
\n" ); document.write( "\"+%28.6a+%2B+3.9%29+%2F+%28+a+%2B+30%29+=+.5+\"
\n" ); document.write( "\"+%28.6%2A111+%2B+3.9%29+%2F+%28+111+%2B+30%29+=+.5+\"
\n" ); document.write( "\"+%28+66.6+%2B+3.9%29+%2F+141+=+.5+\"
\n" ); document.write( "\"+70.5+%2F+141+=+.5+\"
\n" ); document.write( "\"+70.5+=+.5%2A141+\"
\n" ); document.write( "\"+70.5+=+70.5+\"
\n" ); document.write( "OK
\n" ); document.write( "
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