document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=455093>Question 455093</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help again,  Thanks<BR>\n" );
document.write( "The formula r= 2sqrt 5L can be used to approximate the speed r in miles per hr of a car that has left skid marks of length L in feet.  How far will a car skid at 60 mph? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #312431 by </B><A HREF=/tutors/aboutme.mpl?userid=amoresroy><B>amoresroy(361)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amoresroy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=amoresroy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=312431\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given:<BR>\n" );
document.write( "   r = 2(5L)^1/2\r<BR>\n" );
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document.write( "where r = 60<BR>\n" );
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document.write( "     60 = 2(5L)^1/2<BR>\n" );
document.write( "     30 = (5L)^1/2<BR>\n" );
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document.write( "Square both sides<BR>\n" );
document.write( "    900 = 5L<BR>\n" );
document.write( "      L = 180\r<BR>\n" );
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document.write( "The car will skid 180 ft.\r<BR>\n" );
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document.write( "     </SPAN>\n" );
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