document.write( "Question 454861: Trains A and B are traveling in the smae direction on parallel tracks. Train A is traveling at 100 mph and train B is traveling 110 mph. Train A passes a station at 11:15am. If train B passes the same station at 11:27am at what time will train B catch up to train A?\r
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Algebra.Com's Answer #312398 by ankor@dixie-net.com(22740)\"\" \"About 
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Trains A and B are traveling in the same direction on parallel tracks.
\n" ); document.write( "Train A is traveling at 100 mph and train B is traveling 110 mph.
\n" ); document.write( " Train A passes a station at 11:15am.
\n" ); document.write( " If train B passes the same station at 11:27am at what time will train B catch up to train A?
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\n" ); document.write( "From the given information, we know that Train B is 12 min behind A at at 11:15 pm
\n" ); document.write( "therefore Train B is:
\n" ); document.write( "\"12%2F60\" * 110 = 22 miles behind Train A at that time.
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\n" ); document.write( "Let t = time required for Train B to catch Train A
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\n" ); document.write( "Write a distance equation; dist = speed * time
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\n" ); document.write( "Train B dist = Train A dist + 22 mi
\n" ); document.write( "110t = 100t + 22
\n" ); document.write( "110t - 100t = 22
\n" ); document.write( "10t = 22
\n" ); document.write( "t = \"22%2F10\"
\n" ); document.write( "t = 2.2 hrs for B to catch A
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\n" ); document.write( "Convert 2.2 hrs to hrs and minutes: 2 + .2(60) = 2 hr 12 min
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\n" ); document.write( "Find the time from 11:15 pm:
\n" ); document.write( "11:15 + 2:12 = 1:27 pm, Train B catches Train A
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\n" ); document.write( "We can check this by using relative speed between the trains, which is 10 mph
\n" ); document.write( "How long to cover 22 mi at 10 mph? \"22%2F10\" 2.2 hrs which is 2 hrs 12 min
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