document.write( "Question 454952: graph the equation using the slope and the y-intercept\r
\n" ); document.write( "\n" ); document.write( "y=4/3x+2
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Algebra.Com's Answer #312370 by algebrahouse.com(1659)\"\" \"About 
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\"graph the equation using the slope and the y-intercept\"\r
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\n" ); document.write( "\n" ); document.write( "Slope-intercept form is y = mx + b
\n" ); document.write( "m is the slope {rise/run}
\n" ); document.write( "b is the y-intercept {where the line crosses the y-axis}\r
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\n" ); document.write( "\n" ); document.write( "y = (4/3)x + 2
\n" ); document.write( "slope = 4/3
\n" ); document.write( "y-intercept = 2\r
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\n" ); document.write( "\n" ); document.write( "To graph:
\n" ); document.write( "- put a point on 2 on the y-axis
\n" ); document.write( "- from there, go up 4 and to the right 3 and put another point
\n" ); document.write( "{since the slope is 4/3, the line rises 4 for every 3 it goes to the right}
\n" ); document.write( "- draw a line through the two points
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