document.write( "Question 454931: The length of a rectangle is 4m longer than its width.
\n" ); document.write( "If the perimeter of the rectangle is 40m , find its area \n" ); document.write( "

Algebra.Com's Answer #312316 by algebrahouse.com(1659) $\"\"$ $\"About$

You can put this solution on YOUR website!
\"The length of a rectangle is 4m longer than its width.
\n" ); document.write( "If the perimeter of the rectangle is 40m , find its area\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "x = width
\n" ); document.write( "x + 4 = length {length is 4 longer than width}\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Perimeter of a rectangle is 2(width) + 2(length.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "2x + 2(x + 4) = 40 {perimeter is 2(width) + 2(length)}
\n" ); document.write( "2x + 2x + 8 = 40 {used distributive property}
\n" ); document.write( "4x + 8 = 40 {combined like terms}
\n" ); document.write( "4x = 32 {subtracted 8 from both sides}
\n" ); document.write( "x = 8 {divided both sides by 4}
\n" ); document.write( "x + 4 = 12 {substituted 8, in for x, into x + 4}\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "width = 8 and length = 12\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Area of a rectangle is width x length\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Area
\n" ); document.write( "= 8(12) {substituted 8 for width and 12 for length}
\n" ); document.write( "= 96 m² {multiplied}
\n" ); document.write( "www.algebrahouse.com \n" ); document.write( "

\n" );