document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=454654>Question 454654</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Flight 725 left New York at 10:28 a.m. flying north. Flight 245 left from the same airport at 11:18 a.m. flying south at one hundred twenty kph less than three times the speed of flight 725. At 1:06 p.m. they are 1,030 kilometers apart. From the information given in question 14, what is the average rate of speed for Flight 725?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #312223 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=312223\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Flight 725 left New York at 10:28 a.m. flying north.<BR>\n" );
document.write( " Flight 245 left from the same airport at 11:18 a.m. flying south at one hundred <BR>\n" );
document.write( "twenty kph less than three times the speed of flight 725.<BR>\n" );
document.write( " At 1:06 p.m. they are 1,030 kilometers apart.<BR>\n" );
document.write( " What is the average rate of speed for Flight 725?<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Let s = speed of flt 725<BR>\n" );
document.write( "then it says:<BR>\n" );
document.write( "\"Flt 245 at one hundred twenty kph less than three times the speed of flight 725.\"<BR>\n" );
document.write( "therefore:<BR>\n" );
document.write( "(3s-120) = speed of flt 245<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Find the flying time of each aircraft change 1:06 to 13:06<BR>\n" );
document.write( "Flt 725: 13:06 to 10:28: 12:66 - 10:28 = 2 hr 38 min or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=158%2F60 ALIGN=MIDDLE  ALT=\"158%2F60\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 79/30 hrs<BR>\n" );
document.write( "Flt 245: 13:06 to 11:18: 12:66 - 11:18 = 48 min or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4%2F5 ALIGN=MIDDLE  ALT=\"4%2F5\"   DISABLED_style= \"max-width:90%; height:auto;\" > hrs<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Write a distance equation: dist = speed * time<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Flt 725 dist + Flt 245 dist = 1030 km<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=79%2F30 ALIGN=MIDDLE  ALT=\"79%2F30\"   DISABLED_style= \"max-width:90%; height:auto;\" >s + <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4%2F5 ALIGN=MIDDLE  ALT=\"4%2F5\"   DISABLED_style= \"max-width:90%; height:auto;\" >(3s-120) = 1030 <BR>\n" );
document.write( "Multiply by 30, results:<BR>\n" );
document.write( "79s + 6*4(3s-120) = 30(1030)<BR>\n" );
document.write( "79s + 24(3s-120) = 30900<BR>\n" );
document.write( "79s + 72s - 2880 = 30900<BR>\n" );
document.write( "151s = 30900 + 2880<BR>\n" );
document.write( "151s = 33780<BR>\n" );
document.write( "s = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=33780%2F151 ALIGN=MIDDLE  ALT=\"33780%2F151\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "s = 223.7 km/hr is flt 725<BR>\n" );
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