document.write( "Question 47148This question is from textbook advanced mathematical concepts precalculus with applications
\n" ); document.write( ": determine how many times -1 is a root of x^3+2x^2-x-2=0 then find the other roots
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Algebra.Com's Answer #31222 by Earlsdon(6294)\"\" \"About 
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If x = -1 is a root of\"x%5E3%2B2x%5E2-x-2+=+0\", then x+1 is a factor of this polynomial.
\n" ); document.write( "You can find the other factors and, hence, the other roots, by dividing the given polynomial by the factor (x+1)\r
\n" ); document.write( "\n" ); document.write( "\"%28x%5E3%2B2x%5E2-x-2%29%2F%28x%2B1%29+=+x%5E2%2Bx-2\" Now factor the right side.
\n" ); document.write( "\"x%5E2%2Bx-2+=+%28x%2B2%29%28x-1%29\"\r
\n" ); document.write( "\n" ); document.write( "Now we have:\"x%5E3%2B2x%5E2-x-2+=+%28x%2B1%29%28x%2B2%29%28x-1%29\" and...
\n" ); document.write( "\"%28x%2B1%29%28x%2B2%29%28x-1%29+=+0\" Applying the zero products principle, we get:
\n" ); document.write( "\"x%2B1+=+0\" and \"x+=+-1\"
\n" ); document.write( "\"x%2B2+=+0\" and \"x+=+-2\"
\n" ); document.write( "\"x-1+=+0\" and \"x+=+1\"
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