document.write( "Question 5912: HELP...i got 2 different answers from two tutors...solve this quadratic inequality. \r
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document.write( "25x^+16<40x...My answer was x<4/5\r
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document.write( "one tutor agreed and one said there was no solution as you can not take the sqrt of zero...anybody out there that can knows for sure??\r
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document.write( "Thanks Caroline \n" );
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Algebra.Com's Answer #3122 by Abbey(339)![]() ![]() ![]() You can put this solution on YOUR website! I answered you incorrectly. I read this as \n" ); document.write( "\n" ); document.write( "To solve this problem:\r \n" ); document.write( "\n" ); document.write( "25x^2+16<40x \n" ); document.write( "set this as an equal sign: \n" ); document.write( "25x^2+16=40x \n" ); document.write( "subtract 40x from both sides: \n" ); document.write( "25x^2-40x+16=0 \n" ); document.write( "(5x-4)(5x-4)=0 \n" ); document.write( "x=4/5 You have two choices: your solution set can be from negative infinity to 4/5 or from 4/5 to infinity:\r \n" ); document.write( "\n" ); document.write( "Test using the numbers 3/5 (if the solution set is less than 4/5 then this number will be included) Make a second test with the number 1 (if the solution set is from 4/5 to infinity, then the number 1 will be included in the set):\r \n" ); document.write( "\n" ); document.write( "If we put 1 back into the equation: \n" ); document.write( "25(1)^2+16<40(1) \n" ); document.write( "25(1)+16<40 \n" ); document.write( "41<40 THIS IS NOT A TRUE STATEMENT, SO THE SOLUTION SET IS NOT GREATER THAN 4/5.\r \n" ); document.write( "\n" ); document.write( "25(3/5)^2+16<40(3/5) \n" ); document.write( "25(9/25)+16<24 \n" ); document.write( "9+16<24 \n" ); document.write( "25<24. This is not a true statement so the solution set cannot be less than 4/5 either\r \n" ); document.write( "\n" ); document.write( "so there is not a solution to this problem. \n" ); document.write( " |